29. Find the area of a regular hexagon with apothem of 6 inches.

Answer:124.7 in² Step-by-step explanation:A hexagon consists of six equilateral triangles, each of side a, and we can divide each of them into two right triangles. So, we can calculate the area of one right triangle and multiply by 12. The formula for the area of one triangle is A = ½bh Step 1. Calculate the length of the side a Per the Pythagorean Theorem, [tex]\begin{array}{rcl}h^{2} + \left(\dfrac{a}{2}\right)^{2} & = & a^{2} \\\\6^{2} + \dfrac{a^{2}}{4} & = & a^{2}\\\\36 & = &\dfrac{3a^{2}}{4}\\\\144 & = & 3a^{2}\\\\\end{array}\\\\[/tex][tex]\begin{array}{rcl}a^{2} & = & \dfrac{144}{3}\\\\a & = & \dfrac{12}{\sqrt{3}}\\\\a & = & \dfrac{12\sqrt{3}}{3}\\\\a & = & 4\sqrt{3}\\\\\end{array}[/tex] 2.Calculate the area of a small triangle The base of a small triangle is  b = ½a = ½ × 4√3 = 2√3 The area of one small triangle is A = ½ bh = ½× 2√3 × 6 = 6√3 in² 3. Calculate the area of the hexagon A = 12 × 6√3 = 72√3 = 124.7 in²