I WILL AWARD BRAINLIEST!! PLEASE HELP!! Solve the equations for x: 1) a−(a+b)x=(b−a)x−(c+bx), if b≠ 0 x = _______, if b ≠ _______ 2) 2(3x−5a)+9(2a−7b)+3(5a−2x)=0; if a = 63b/23 then x = ________ if a ≠ 63b/23 then x = ________

Answer:1) x = (a+c)/b2) The equation is correct no matter what value x takes.Step-by-step explanation:1) a−(a+b)x=(b−a)x−(c+bx)<=> a - ax - bx = bx - ax - c - bx<=> a - ax - bx - (bx - ax - c - bx) = 0<=> a - ax - bx - bx + ax + c + bx = 0<=> a - ax + ax - bx - bx + bx + c = 0<=> a - bx + c = 0<=> bx = a + cIf b ≠ 0, x = (a+c)/b2) 2(3x−5a)+9(2a−7b)+3(5a−2x)=0<=> 2×3x + 2×(-5a) + 9×2a + 9× (-7b) + 3×5a + 3×(-2x) = 0<=> 6x -10a + 18a - 63b + 15a - 6x = 0<=> (6x - 6x) + (15a - 10a + 18a) - 63b = 0<=> 23a - 63b = 0<=> 23a = 63b=> a = 63b/23with all values of x, the equation is correct.