the sum of the reversed number and the original number is 154. Find the original number, if the ones digit in it is 2 less than the tens digit.

Answer:  86==========================================================Explanation:For the original two digit number, we have: x = tens digity = units digit (aka ones digit)The original number is 10x+y. For instance, if x = 5 and y = 7, then we have 10x+y = 10*5+7 = 57.This original number 10x+y swaps its digits to 10y+x. Then we add up the two expressions:(original)+(swapped) = (10x+y)+(10y+x) = 11x+11y = 11(x+y)This sum is stated to be 15411(x+y) = 154x+y = 154/11x+y = 14Then we're told that "the ones digit in it (the original number) is 2 less than the tens digit". Meaning that y = x-2 is another equation we can use. We'll plug this into the previous equation we found and solve for xx+y = 14x+x-2 = 14 ... replace y with x-22x-2 = 142x = 14+22x = 16x = 16/2x = 8 is the tens digit of the original numbery = x-2y = 8-2y = 6 is the units digit of the original numberThe original number is 10x+y = 10*8+6 = 86As a check, adding 86+68 = 154 which confirms our answer.