What is the concentration of nitrate ions in a 0.125 M Mg(NO3)2 solution
Accepted Solution
A:
The dissociation of Mg(NO₃)₂ can be expressed as follow,
Mg(NO₃)₂ --> Mg²⁺ + 2NO₃⁻
Each mole of the Mg(NO₃)₂ will dissociate into 2 moles of NO₃⁻. Thus, to determine the concentration of the nitrate ions, we multiply the given value of two. M = (0.125M)(2) = 0.250M